Smocking is done on pairs of columns marked with diagonals together. After completing one pair of column we have to move on to the next pair.

**Width of the material after smocking**

After smocking the width of one pair of column of squares become equal to ½ if the diagonal of the square used.he gap takes the shape of an equilateral triangle (See the diagram 1) whose side is equal to the diagonal of the square. Width of the gap will be equal to the height of the triangle thus formed.

Height of the triangle can be calculated by using the diagonal of the square used

Height of the triangle =√ (diagonal²–½diagonal²) .No need to worry about the formula. I have given the table which gives the diagonal and height of the triangle formed when smocking is done on different sizes of squares.

**Length**

After smocking the height of two rows will be equal to the diagonal of the square

With the help of these calculations we can find out the number of squares we need in each row and in each column. And then the material needed..Figures3,4and 5 explain the changes that take place after smocking for different sizes of squares

I will give one example

How to calculate material needed for a cushion of size 40cm x40cm smocking done on graph with squares 3cm x 3cm

Width

After smocking width first column becomes half of the diagonal =2.1cm

Width of next gap will be equal to height of the triangle formed = 3.6cm

Total of these three squares will be 5.7cm

These three squares are repeated

Last column is column of squares with diagonals (marked pink) its width is 2.1cm

Subtract 2.1 cm from 40 cm =37.9 cm

Now we have to find out how many times the fist 3 squares whose width will be 5.7 can be repeated to get to get 37.9cm

37.9cm÷ 5.7= 6.6

We can repeat 6 times without fraction that means we have to repeat 3 squares 6 times

3x6= 18 squares + last column 2 squares. = 20 squares

If you smock on 20 squares resulting material will be (8x 5.7) + 2.1= 34.2 cm + 2.1cm= 36.3 cm

It is 37 cm approximately or 4cm less than 40 cm this can be made up by adding 2 cm on either side as border to this add 1cm on either side for seams

Length

We get 4, 2 cm when we smock 2 rows

These two rows should be repeated 40 ÷ 4.2= 9.5 times or 9 times without taking decimal

2 rows X 9 = 18 rows. When we smock these 18 rows the length we get = 4.2 x 9= 37.8 cm

It is 2.2 cm less than 40 cm. it can be made up by adding 1 .1 cm on either side. To this add 1 cm on either side as border.

So the graph will have 18 rows each row having 20 squares

Width of the material=20 squares x 3cm=60cm + 6cm=66cm

Length of the material = 18 X 3 cm =54 cm + 4.2 cm=56.2 cm

Material needed =66 cm Χ 56.2 cm

hi i m jathavi, i m fashion designing student ........ur information is very much useful to me...thanksssssss a lot

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ReplyDeleteall ur post are useful can u plz add the finishing points which ll be understand even more better:)) thanks alot for ur sharing

ReplyDeleteGritns! Tanks for d post. I wud love to teach my nieces dz designs for d summer but m just not good at maths. Pls s ther an easier way to learn ds? U wud rily put a smile on my face and ild b most grateful. Tank u.

ReplyDeleteThank you for this explanation. I shall have to go and do a bit of calculating now, but I am glad to have some sort of formula to start from.

ReplyDelete